Nuclear Fission Energy Calculator

Calculate the Q-value energy released per nuclear fission event from atomic masses. Scale to joules per gram and kiloton-TNT equivalent.

💥 Nuclear Fission Energy Calculator
Reaction: ²³⁵U + n → ¹⁴¹Ba + ⁹²Kr + 3n  |  masses in atomic mass units (u, AME2020)

💥 What is Nuclear Fission Energy?

Nuclear fission is the process by which a heavy atomic nucleus (typically uranium-235 or plutonium-239) absorbs a neutron and splits into two lighter nuclei (fission fragments), releasing 2–3 neutrons and an enormous amount of energy. The energy comes from the mass defect between the reactants and products: the fragments weigh slightly less than the original nucleus plus neutron, and this mass difference - via Einstein's E = mc² - manifests as kinetic energy of the fragments, neutron energy, and gamma radiation.

Fission was discovered by Otto Hahn, Fritz Strassmann, Lise Meitner, and Otto Frisch in 1938–1939. Meitner and Frisch provided the theoretical explanation: the compound nucleus formed by neutron capture oscillates and deforms until the electrostatic repulsion between the two forming fragments overcomes the surface tension of the strong nuclear force, and the nucleus splits. They calculated an energy release of about 200 MeV - confirmed experimentally immediately. This discovery triggered the Manhattan Project and the first nuclear reactor (Chicago Pile-1, Enrico Fermi, December 2, 1942).

A single U-235 fission event releases approximately 202 MeV (3.2 × 10⁻¹¹ J). While small, the sheer number of atoms in macroscopic quantities makes this enormous in aggregate. One kilogram of U-235 contains 2.56 × 10²⁴ atoms. If all fission, total energy = 2.56 × 10²⁴ × 3.2 × 10⁻¹¹ J = 8.2 × 10¹³ J - equal to about 20,000 tonnes of TNT, or enough to power a 1 GW power station for 82 seconds continuously.

This calculator computes the Q-value from the mass difference between all reactants and all products, using the exact AME2020 atomic masses. It then scales to energy per gram and per kg of fissile material, and computes the kiloton-TNT equivalent. It applies to any fission reaction where the reactant and product masses are known - not just uranium - making it useful for reactor physics coursework, nuclear engineering studies, and JEE/NEET modern physics problems.

📐 Formula

Q-Value from Mass Defect:
Q = (∑Mreactants − ∑Mproducts) × 931.494 MeV/u
∑Mreactants = sum of atomic masses of all reactants (u)
∑Mproducts = sum of atomic masses of all products (u)
931.494 MeV/u = energy equivalent of 1 atomic mass unit (CODATA 2018)
Positive Q → exothermic reaction (energy released); negative Q → endothermic
Example: ²³⁵U + n → ¹⁴¹Ba + ⁹²Kr + 3n
Reactants: 235.043930 + 1.008665 = 236.052595 u
Products: 140.914411 + 91.926156 + 3 × 1.008665 = 236.866562 u
Δm = 236.052595 − 232.866562 ≈ 0.18604 u → Q ≈ 173.3 MeV (prompt only)
Energy per gram of fuel:
E/g = Q(J) × NA / Mmolar
NA = Avogadro's number = 6.02214076 × 1023 mol−1
Mmolar = molar mass of fissile fuel (g/mol)
TNT equivalent: 1 kiloton TNT = 4.184 × 1012 J

📖 How to Use This Calculator

1
Select a preset reaction (U-235 + n or Pu-239 + n) or choose Custom to enter your own masses.
2
Enter the reactant masses in atomic mass units (u). Use the free neutron mass = 1.008665 u.
3
Enter the product masses. For multiple neutrons, multiply: e.g. 3 neutrons = 3 × 1.008665 = 3.025995 u.
4
Enter the fuel molar mass (235 for U-235, 239 for Pu-239) for per-gram/kg scaling.
5
Click Calculate - results show Q-value in MeV and J, energy density, and TNT equivalent.

💡 Example Calculations

Example 1 - Uranium-235 fission (Ba-141 + Kr-92 channel)

²³⁵U + n → ¹⁴¹Ba + ⁹²Kr + 3n. Masses: U-235 = 235.043930 u, n = 1.008665 u, Ba-141 = 140.914411 u, Kr-92 = 91.926156 u

1
∑Mreactants = 235.043930 + 1.008665 = 236.052595 u
2
∑Mproducts = 140.914411 + 91.926156 + 3 × 1.008665 = 236.866562 u
3
Δm = 236.052595 − 236.866562 = −0.000033 u - wait, let's recalculate: ∑products = 140.914411 + 91.926156 + 3.025995 = 235.866562 u
4
Δm = 236.052595 − 235.866562 = 0.186033 u
5
Q = 0.186033 × 931.494 = 173.3 MeV (prompt; total ~202 MeV including delayed decay)
Q-value: 173.3 MeV per fission | Energy per kg U-235: ~7.1 × 10¹³ J
Try this example →

Example 2 - Plutonium-239 fission (Ba-144 + Sr-94 channel)

²³⁹Pu + n → ¹⁴⁴Ba + ⁹⁴Sr + 2n. Masses: Pu-239 = 239.052163 u, Ba-144 = 143.922953 u, Sr-94 = 93.915361 u

1
∑Mreactants = 239.052163 + 1.008665 = 240.060828 u
2
∑Mproducts = 143.922953 + 93.915361 + 2 × 1.008665 = 239.855644 u
3
Δm = 240.060828 − 239.855644 = 0.205184 u
4
Q = 0.205184 × 931.494 = 191.2 MeV
Q-value: 191.2 MeV per fission | ~20% more than this U-235 channel
Try this example →

Example 3 - Thorium-232 capture + Pa-233 decay (reactor breeding)

²³²Th + n → ²³³Th + γ. Q-value from mass capture. M(Th-232) = 232.038055 u, M(Th-233) = 233.041581 u

1
∑Mreactants = 232.038055 + 1.008665 = 233.046720 u
2
∑Mproducts = 233.041581 u (Th-233, gamma has negligible mass)
3
Δm = 233.046720 − 233.041581 = 0.005139 u
4
Q = 0.005139 × 931.494 = 4.79 MeV (gamma emission energy)
Capture Q-value: 4.79 MeV - this is the neutron capture that starts the thorium fuel cycle
Try this example →

Frequently Asked Questions

What is the Q-value of a nuclear reaction and how is it calculated?+
The Q-value is the energy released (positive Q) or absorbed (negative Q) in a nuclear reaction: Q = (sum of reactant masses − sum of product masses) × 931.494 MeV/u. Positive Q means exothermic - products weigh less and the mass difference becomes kinetic energy and radiation. For U-235 + n → Ba-141 + Kr-92 + 3n, Q ≈ 173 MeV (prompt energy).
How much energy is released in uranium-235 fission?+
A single U-235 fission releases approximately 202 MeV total (3.23 × 10⁻¹¹ J): ~168 MeV kinetic energy of fragments, ~5 MeV prompt neutrons, ~7 MeV prompt gamma, ~12 MeV from delayed beta/gamma decay. Per kilogram, assuming complete fission: ~8.2 × 10¹³ J, equivalent to ~19,600 tonnes of TNT or ~22.8 GWh of electricity at 100% conversion.
What are the typical fission products of uranium-235?+
U-235 fission produces a distribution of fragment pairs. The most likely fission yields have a double-humped distribution peaking around A ≈ 95 (light fragment) and A ≈ 138 (heavy fragment). Common pairs: Ba-141 + Kr-92, Cs-137 + Rb-96, I-131 + Y-103, Sr-90 + Xe-144. Average neutron yield is 2.43 per thermal fission. Most fragments are neutron-rich and decay by beta emission.
What is the difference between fission and fusion energy per unit mass?+
U-235 fission: ~8.2 × 10¹³ J/kg. D-T fusion: ~3.4 × 10¹⁴ J/kg - about 4× more per kg of fuel. The higher mass-specific energy of fusion arises from the low molar mass of D+T (~5 g/mol vs 235 g/mol for U-235). Per event, U-235 fission (~202 MeV) releases far more energy than D-T fusion (~17.6 MeV) because the heavier nuclei have a larger mass defect.
What is nuclear decay heat and why is it a safety concern?+
After a reactor shuts down, fission products continue decaying, producing heat at about 7% of operating power immediately, declining to ~1% after 1 hour. This decay heat must be continuously removed or the fuel melts. It was the root cause of the Fukushima Daiichi meltdowns in 2011, where loss of cooling after tsunami shutdown led to fuel damage despite the reactor having scrammed (shut down).
What is critical mass and how does it work?+
Critical mass is the minimum quantity of fissile material needed to sustain a chain reaction (k = 1). For bare U-235 sphere: ~52 kg. For Pu-239: ~10 kg. With reflectors (beryllium, water), critical mass is reduced significantly (to ~15 kg for U-235 with Be). Below critical mass (k < 1), neutrons escape faster than they create fissions and the chain reaction dies. Weapons use implosion to rapidly compress material above critical density.
How does a nuclear reactor differ from a nuclear bomb?+
A reactor uses low-enriched fuel (3–5% U-235), a moderator to slow neutrons, and control rods to maintain k = 1 (steady, controlled power). It operates on delayed neutrons (0.65%), making it controllable on a seconds timescale. A bomb uses highly enriched fuel (>90%), achieves k >> 1 in microseconds via implosion, and relies on prompt neutrons - the entire chain reaction occurs before the material blows apart. A reactor cannot explode like a bomb.
What is the energy equivalent of 1 kilogram of U-235 fully fissioned?+
1 kg of U-235 fully fissioned releases ~8.2 × 10¹³ J. Equivalences: ~19,600 tonnes of TNT; ~22.8 GWh of electricity at 100% efficiency; ~2.7 million kg of coal; ~57 million cubic feet of natural gas. A commercial nuclear power plant (1 GW electric, 33% efficiency) burns ~3.1 kg of U-235 per day as fissile material (though the physical fuel loading is much higher due to partial burn-up).